4 is an aliquot part of 12.
4 能除12。
This paper studies the numeral divisibility characteristic of round number, and solves the problem in theory about the divisibility characteristic of any round number.
摘要针对的除特了研究,从理上解决了任意的除特问题。
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2,4,6, and 8 are even numbers and can be divided exactly by 2.
2、4、6、8是偶数,且可被2整除。
I know that because two is divisible into eight.
我知道这个 因为8能被2整除。
I will switch every light bulb that's divisible by two.
我会按下编号能被2整除的那些灯泡。
A quantity of pearls that can appease the sea monsters must be divisible by 7,11, and 13.
能平息海怪的珍珠数量必须能被 7、11、和 13 整除。
Being divisible by 7,11, and 13 means that our number must be a multiple of 7,11, and 13.
能被 7、11、和 13 整除,说明这个数必须同时是 7、11、和 13 的倍数。
The lowest common denominator, for example, is the smallest number that can be divided evenly into a set of fractions.
例如," 最小公分母(The lowest common denominator)" 是指能被一组分数整除的最小的数。
12 is a whole, complete, perfectly divisible number.
12 是一个完整的、完整的、可以完全整除的数。
If not divisible by two, divide by three.
如果不被二整除,则除以三。
But January, 365 is not divisible by 12.
但是一月,365不能被12整除。
A lot of numbers are divisible by 3.
很多数可以被3整除。
And, when it's divisible by both 3, and 5. you print fizzbuzz.
并且,当它可以被 3 和 5 整除时,您将打印 fizzbuzz。
This diagonal is also out, as they’re divisible by 11.
这条对角线也不对, 因为它们可以被 11 整除。
" Even" (even) is used for any number that you can divided evenly by the number two.
“偶数”是指任何可以被2整除的数。
Any one-gem advantage where your starting total is divisible by three will lead to victory by the same logic.
如果您的起始总数可以被三整除,任何一颗宝石的优势都会按照相同的逻辑导致胜利。
We can eliminate anything that ends in 2 or 5, as they’ll always be divisible by 2 and 5.
我们可以消除任何以 2 或 5 结尾的东西,因为它们总是可以被 2 和 5 整除。
You might remember this from elementary school math, but a prime number is only divisible by itself and 1.
你可能还记得这个小学数学的知识点,素数只能被它自己和1整除。
Well, the slime-lined are in their prime— which is to say they’re prime numbers, divisible only by 1 and themselves.
好吧, 粘液衬里处于质数状态——也就是说它们是质数,只能被 1 和它们自己整除。
These major aspects are those that are divisible by 10 and evenly divided in relation to the 360 degree wheel.
这些主要相位是指那些能被10整除,并且在360度圆盘中均匀分布的相位。
To simplify this, both of these equations, actually the top one and the bottom one, both sides are divisible by 2n.
为了简化这一点, 这两个方程,实际上是上面的那个和下面的那个, 两边都可以被2n整除。
This covers every number which divides evenly into 45, once, and only once.
这涵盖了所有能被45整除一次且仅一次的数。
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