有奖纠错
| 划词

It is indicated by experimention that the outcome of this algorithm is very efficient,especially in those problem who fulfil triangle inequation.

实验表明,此类算法求解的近似度很高,其是在满足三角不等式的问题中,误差

评价该例句:好评差评指正

用户正在搜索


Amish, amisometradine, amiss, amistad, Amitabha, amital, amiterol, amithiozone, amitosis, amitotic,

相似单词


3G, 401(K), a,

声明:以上例句、词性分类均由互联网资源自动生成,部分未经过人工审核,其表达内容亦不代表本软件的观点;若发现问题,欢迎向我们指正。

可汗学院:统计学(视频版)

So what I'm going to do is multiply this entire inequality by negative 1.

所以要做的是将整个不等式乘以负1。

评价该例句:好评差评指正
可汗学院:统计学(视频版)

Just be clear, I'm just multiplying all three sides of this inequality by this number right over here.

明确一点,只是将这个不等式的所有个方面乘以这里的这个字。

评价该例句:好评差评指正
高等学之美

Well, he and I just made a video on a certain quantum mechanical topic - " Bell's inequalities" .

嗯,他和制作了一个关于某个量子力学主题的视频——“贝尔不等式”。

评价该例句:好评差评指正
可汗学院:统计学(视频版)

But since we are multiplying an inequality by a negative number you have to swap the inequality sign.

但是由于们将不等式乘以负,因此您必须交换不等号。

评价该例句:好评差评指正
耶鲁大学公开课:博弈论

So, in here, the inequality is met: the sum is bigger than 1; and out here it's less than 1.

因此,在这里,不等式得到满足:总和大于 1;而在这里它小于 1。

评价该例句:好评差评指正
高等学之美

But of course, for those of you who want some more passive viewing, don't forget that Henry and I just put out a video on Bell's inequalities over on MinutePhysics.

当然, 对于那些想要更被动观看的人来说,不要忘记亨利和在 MinutePhysics 上发布了一段关于贝尔不等式的视频。

评价该例句:好评差评指正
可汗学院:统计学(视频版)

So if I do that-- so let me just do that right over-- so if I multiply this entire-- this is really two equations or two inequalities I should say.

因此,如果这样做——那么让重新做一遍——所以如果将其全部相乘——应该说这实际上是两个方程或两个不等式

评价该例句:好评差评指正

用户正在搜索


Amman, Ammanian, Ammate, ammersoaite, ammersooite, ammeter, ammine, ammino, ammino-complex, ammiol,

相似单词


3G, 401(K), a,
  • 微信二维码

    关注我们的微信

  • 手机客户端二维码

    下载手机客户端

赞助商链接