Computers operate using binary numbers.
计算机运行运用二制。
In 1971 Britain changed over from pounds, shillings, and pence to the new decimal money system.
九七英国把英镑、先令、士改为新的十制。
With the addition of the toes on our feet a vigesimal (base 20) number system, like that of the Maya, also makes sense.
再加上我们的双脚的脚趾,二十(以20为基数)数字体系也是合情合理的。
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Or in a given row, treat each number as part of a decimal expansion.
或是将其中一列作十进位展。
Turning switch 11 on gives us 110 by standard binary addition.
根据标准二元进位法,如果 11,们会得到 110。
Each bit can be either a zero or a one in the binary language of computing.
计算机的二进位语言中,每个比特代表0或1。
Although recording methods have changed, the decimal system has triumphed throughout.
虽然记录方法发生了变化,但十进位制整个过程中占着主导地位。
But, we need an extra output wire for that carry bit.
但是,们需要一个额外的输出线用于那个进位。
But then I mean the last two weeks it's only two carries.
但的意思是过去两周只有两次进位。
Well, they don't do carrying over like we used to do.
算进位的方法已经跟们当年不一样了。
So two carries inside the five.
所以五个进位里面有两个进位。
Um, but looking at like five zone carries, no, that's, that's the money.
嗯,但是看看五个区域的进位,不,就是这样,这就是钱。
And this is going to be- Five zone carries.
这将是——五区进位。
You have two inputs, A and B, and you have a sum output and a carry output.
您有两个输入 A 和 B,并且有一个总和输出和一个进位输出。
That is- Eight five zone carries.
那就是——八个五区进位。
An additional downside is that it takes a little bit of time for each of the carries to ripple forward.
另一个缺点是每个进位需要一点时间才能向前波动。
Obviously, 27 carries is a very outrageous number.
显然,27次进位是一个非常离谱的数字。
Now we add 8 plus 1 plus the 1 we carried, that's 10, so the sum is 0 carry 1.
们加上 8 加 1 再加上们进位的 1,就是 10,所以和是 0 进位 1。
Notice how the carry bits ripple forward to each subsequent adder.
请注意进位位如何波及到每个后续加法器。
For this reason, this is called an 8-bit ripple carry adder.
因此,这被称为 8 位纹波进位加法器。
I think that's what's nice is this was not dependent on 20 carries.
认为这很好,因为这不依赖于 20 个进位。
That's why you had 26 carries. He looked good and man is that Raiders locker room.
这就是为什么你有 26 次进位。他看起来不错,而且是突袭者更衣室里的那个人。
Lastly, we need a OR gate to check if either one of the carry bits was true.
最后,们需要一个或门来检查其中一个进位是否为真。
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